DP solution is ..

c[i][j] = min (c[i][k] + c[k][j] + (a[j]-a[i])) where j>i & k=i+1 to
j-1
c[i][j] = a[j]-a[i] when j=i+1

c[i][j] indicates the minimum cost to cut the log starting at a[i] and
ending at a[j]...

c[0][n] gives the answer..

correct me if i am wrong or any better solutions?

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