Oh. That is supposed to be t. So the line actually could read t /= 10000; Sorry for the typo.
Dave On Feb 4, 11:58 am, Rahul Verma <rahulverma....@gmail.com> wrote: > @Dave > In the line t=p/1000000; > what is the value of p here or what it means? > > On Feb 4, 9:57 pm, Dave <dave_and_da...@juno.com> wrote: > > > > > @Rahul: Given that 100! < 100^100 = 10^200, we know that 100! has less > > than 200 digits. Assuming 32-bit integers, we might choose to store > > anywhere from 1 to 7 digits in an integer, realizing that we have to > > multiply the integer by a number up to 100 and still want the result > > to be less than 2^31. I'll use 5 digits in an integer. Then the > > computation can look something like this, assuming that you have > > already read n, the number whose factorial you want: > > > int a[40], i, j, l, t; > > a[0] = 1; // rightmost "digit" of number = 0! > > l = 1; // the active number of elements of a[] used. > > for( i = 2 ; i < n ; ++i ) > > { > > t = 0; // the carry into the next product > > for( j = 0 ; j < l ; ++j ) > > { > > t += i * a[j]; // multiply digit by i and add carry > > a[j] = t % 10000; // extract 5 digits > > t = p / 100000; // calculate next carry > > } > > if( t > 0 ) // does the number need to add a digit? > > a[l++] = t; > > } > > printf("%i",a[l-1]); > > for( i = l-2 ; i >= 0 ; --i ) > > printf("%.5i",a[i]); > > printf("\n"); > > > Dave > > > On Feb 4, 10:19 am, Rahul Verma <rahulverma....@gmail.com> wrote: > > > > Hi Group, > > > > Let me help to solve this problem of > > > SPOJhttps://www.spoj.pl/problems/FCTRL2/ > > > > The approach to solve the problem is very easy and I'm confused that > > > how to store such a large no. like 100! in a variable using C++ > > > Language. > > > > Thanx & Regards, > > > Rahul Verma- Hide quoted text - > > - Show quoted text - -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.