@priya Because precedence of + operator is greater than "<<" operator . So
evaluation of expression a <<2 + a will be
a<<(a+2)
On Sat, Feb 5, 2011 at 6:35 PM, priya mehta <priya.mehta...@gmail.com>wrote:
> sure thanks:)
>
>
>
> On Sat, Feb 5, 2011 at 6:26 PM, Gajendra Dadheech <gajju3...@gmail.com>wrote:
>
>> @priya u seems to be a beginner in c programming...
>> I would suggest u to go through Dennis richie.....
>>
>> Thanks and regards,
>> Gajendra Dadheech
>>
>>
>>
>>
>> On Sat, Feb 5, 2011 at 2:53 PM, Manmeet Singh <mans.aus...@gmail.com>wrote:
>>
>>> because u not thinking of operator precedence :P :P
>>>
>>>
>>> On Sat, Feb 5, 2011 at 2:52 PM, priya mehta <priya.mehta...@gmail.com>wrote:
>>>
>>>> why is this happening?
>>>>
>>>>
>>>>
>>>> On Sat, Feb 5, 2011 at 2:51 PM, Manmeet Singh <mans.aus...@gmail.com>wrote:
>>>>
>>>>> 8, 32, 96
>>>>>
>>>>> On Sat, Feb 5, 2011 at 2:46 PM, priya mehta
>>>>> <priya.mehta...@gmail.com>wrote:
>>>>>
>>>>>> #include <stdio.h>
>>>>>> #define PrintInt(expr) printf("%s : %d\n",#expr,(expr))
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>> *int* FiveTimes(*int* a)
>>>>>> {
>>>>>> *int* t;
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>> t *=* a*<<*2 *+* a;
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>> *return* t;
>>>>>> }
>>>>>>
>>>>>> *int* main()
>>>>>> {
>>>>>> *int* a *=* 1, b *=* 2,c *=* 3;
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>> PrintInt(FiveTimes(a));
>>>>>> PrintInt(FiveTimes(b));
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>> PrintInt(FiveTimes(c));
>>>>>> *return* 0;
>>>>>> }
>>>>>>
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