@jagan: that's true obj is a pointer to the data type for which size
need to be calculated.

On Feb 7, 10:38 am, jagannath prasad das <jpdasi...@gmail.com> wrote:
> @rajiv:i guess obj is a pointer here........
>
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> On Mon, Feb 7, 2011 at 10:51 AM, Rajiv Podar <rajeevpo...@gmail.com> wrote:
> > Hi
> > Try following code
>
> > Suppose  we need to find size of variable *"obj"*
> > int size = (char*)(obj +1 ) - (char*)(obj);
>
> > *
> > *Thanks & Regards,
> > Ricky
>
> > On Mon, Feb 7, 2011 at 12:19 AM, albert theboss 
> > <alberttheb...@gmail.com>wrote:
>
> >> using this macro
>
> >> size(X)  ((X*)0+1)
>
> >> if we give size(int)  it ll return 4.
> >> size(double)  gives 8.
>
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