@ashish: tht's true. But that will be the sum of two numbers.
Reason is v store the address in char* so when increment it by other number it
will increment that times, that is the required answer.
Sent from my iPod
On Feb 7, 2011, at 7:14 PM, Ashish Goel <ashg...@gmail.com> wrote:
> &p[n] gives address of p+n it does not add..
> Best Regards
> Ashish Goel
> "Think positive and find fuel in failure"
> +919985813081
> +919966006652
>
>
> On Mon, Feb 7, 2011 at 11:47 AM, jalaj jaiswal <jalaj.jaiswa...@gmail.com>
> wrote:
> try this
>
> let nos be m & n
>
> char * p;
> p=m;
> int sum = (int)&p[n] ;
>
> sum is m+n :)
>
>
> On Mon, Feb 7, 2011 at 11:41 AM, Dave <dave_and_da...@juno.com> wrote:
> @Ricky: if increment and decrement operators are not considered
> arithmetic, try
>
> int sum(int m, int n)
> {
> while( m > 0 )
> {
> m--;
> n++;
> }
> while( m < 0 )
> {
> m++;
> n--;
> }
> return n;
> }
>
> On Feb 6, 11:49 pm, Ricky <rajeevpo...@gmail.com> wrote:
> > write the program to add two numbers without using arithmetic and bit
> > operation..
>
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> With Regards,
> Jalaj Jaiswal (+919019947895)
> Final Year Undergraduate,
> IIIT ALLAHABAD
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