sorry.
did not go thru it thoroughly earlier.
got it now.

On Feb 9, 7:35 pm, Tushar Bindal <tushicom...@gmail.com> wrote:
> what are f1, f2, f3,...?????
>
>
>
> On Wed, Feb 9, 2011 at 5:05 PM, Ujjwal Raj <ujjwal....@gmail.com> wrote:
> > Input: n meetings
> > A meeting e(i) has start time s(i) and finish time f(i).
> > Sort n events based on there finish time f(i)
> > Say sorted meeting(based on finishing time) are:
> > e1,e2,e3,e4,...en
>
> > E(t): denotes the maximum no of meetings conducted where 0 <= time <= t.
>
> > E(f1) = e1
> > E(f2) = max(E(s2) + 1), E(f1));
> > E(f3) = max(E(s3)+1), E(f2));
>
> > Make array of E based on finishing times.
> > So your array will have values of E at different finishing times
> > f1 E1
> > f2, E2
> > f3 E3
> > f4 E4
>
> > so E2 means maximum no of events between time >= f2 and < f3.
>
> > Hope it is now clear.
>
> > On Wed, Feb 9, 2011 at 12:59 PM, Sachin Agarwal <sachinagarwa...@gmail.com
> > > wrote:
>
> >> didn't quite get it, can you please elaborate.
> >> thanks
>
> >> On Feb 8, 10:38 pm, Ujjwal Raj <ujjwal....@gmail.com> wrote:
> >> > Use dynamic programming:
> >> > 1) Sort the events in order of finishing time.
> >> > f1, f2, f3, f4, ... fn
>
> >> > E(fn) = E(sn) + 1;
> >> > Solve the above recursion
> >> > sn is start time of event n
>
> >> > On Wed, Feb 9, 2011 at 11:30 AM, Sachin Agarwal
> >> > <sachinagarwa...@gmail.com>wrote:
>
> >> > > Suppose I have a room and I want to schedule meetings in it. You're
> >> > > given a list of meeting start and end times. Find a way to schedule
> >> > > the maximum number of meetings in the room.
>
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> --
> Tushar Bindal
> Computer Engineering
> Delhi College of Engineering
> Mob:+919818442705begin_of_the_skype_highlighting            +919818442705      end_of_the_skype_highlighting
> E-Mail : tusharbin...@jugadengg.com, tushicom...@gmail.com

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