well its game of Number Theory There are 3 possibilities in any number set - prime numbers, non-prime numbers (that are not squares) & squares.
In this puzzle the original state of a door will be reversed if it is acted upon an odd number of times - otherwise the original state & the final state will be the same. Now let us take each of the number types I mentioned above. its another Explanation How I will Approach to the Problem... 1. Prime numbers are divisible by themselves & 1 - so they will be acted upon an even number of times. So these doors (corresponding to prime numbers) will be closed 2. Non-prime non-square numbers(15,27 etc) are divisible by themselves, 1, & any other two numbers such as a*b where a is not equal to b. Thus they are divisible at least by 4 numbers - which means these doors will be closed as well. 3. Square numbers are divisible by themselves, 1 & its factors a*a. Since the factors are the same, these numbers are divisible by at least 3 numbers - hence these doors will be open Correct me If I am wrong... Another Approach will b appreciated Thanks & Regards Shashank Mani >> ""The best way to escape from a problem is to solve it."" -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
