re.findall(r'a([^a]*)a','000a1111a2222a3333a4444a') On Mar 24, 3:40 pm, DD <dutta.dipanka...@gmail.com> wrote: > >>> re.findall(r'a(.*)a','000a1111a2222a3333a4444a') return > > ['1111a2222a3333a4444'] > > what is the regular expression such that it should return > ['1111','2222','3333','4444'] > > ?
-- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
