The second cost will be 5+23 irrespective of the end. Correct me u think otherwise.
On Mon, Mar 28, 2011 at 10:44 PM, Raunak Agrawal <raunak.ra...@gmail.com>wrote: > @Kunal: > > > Eg: Rope 1: Size 10 mtr > Rope 2: Size 13 mtr > Rope 3: Size 5 mtr > > > Cost of tying rope 1 and rope 2 = 10 +13 = 23 > > Now we have tow end...one for rope 1 and another for rope 2 which can be > tied with rope 3. > > So tie Rope 3 end with rope 2 end : (Length of rope 2 + 3) = (5 + 13) = 18 > > So total cost = 23 +18 = 41. > > > So for different combination we can have different cost....please let me > know in case there is any doubt. > > On Mon, Mar 28, 2011 at 10:35 PM, Kunal <kunal.shrivas...@gmail.com>wrote: > >> If you have already tied ropes 1 and 2 then their final length would be 23 >> now you are left with two ropes o length 23 and 5 which suns out to be 28. >> This remains the same in each of your two examples. >> >> Why did you add 13 twice ? I mean you can tie them in 28 cost if you first >> tie any two and then tie with the left one. Why use 3 knots when it can be >> done in 2 !! >> >> Sent from my iPhone >> >> On Mar 28, 2011, at 8:36 PM, Raunak Agrawal <raunak.ra...@gmail.com> >> wrote: >> >> I think the possible solution is : >> >> *Tie the highest two ropes at the end of the rope.* >> * >> * >> This is because of the following reason: >> >> Eg: Rope 1: Size 10 mtr >> Rope 2: Size 13 mtr >> Rope 3: Size 5 mtr >> >> Rope1--> Rope2--> Rope3 Cost: (10+13) + (13+5) = 41 >> >> Rope1-->Rope3--> Rope2 Cost: (10+5) + (5+13) = 33 >> >> >> So the optimum cost is : *1st Highest length Rope + 2*(Length of all >> other ropes other that two having the highest size) + 2nd Highest Rope*. >> >> >> On Mon, Mar 28, 2011 at 7:49 PM, Gunjan Sharma <<gunjan.khan...@gmail.com> >> gunjan.khan...@gmail.com> wrote: >> >>> The question seems to be correct. Think again.... >>> >>> >>> On Mon, Mar 28, 2011 at 5:24 PM, kunal srivastav >>> <<kunal.shrivas...@gmail.com> >>> kunal.shrivas...@gmail.com> wrote: >>> >>>> if you tie all of them and the cost is sum of invidual lengths then in >>>> the end the cost will be sum of all lengths irrespective of any order that >>>> we tie them in.. >>>> i think the ques would req you to say that the cost is the longer of the >>>> two..plz check >>>> >>>> >>>> On Mon, Mar 28, 2011 at 12:11 PM, bittu < <shashank7andr...@gmail.com> >>>> shashank7andr...@gmail.com> wrote: >>>> >>>>> you are given n ropes,maybe of different length. the cost of tying two >>>>> ropes is the sum of their lengths.Find a way to tie these ropes >>>>> together so that the cost is minimum. >>>>> >>>>> >>>>> >>>>> Thanks >>>>> Shashank >>>>> >>>>> -- >>>>> You received this message because you are subscribed to the Google >>>>> Groups "Algorithm Geeks" group. >>>>> To post to this group, send email to <algogeeks@googlegroups.com> >>>>> algogeeks@googlegroups.com. >>>>> To unsubscribe from this group, send email to >>>>> <algogeeks%2bunsubscr...@googlegroups.com> >>>>> algogeeks+unsubscr...@googlegroups.com. >>>>> For more options, visit this group at >>>>> <http://groups.google.com/group/algogeeks?hl=en> >>>>> http://groups.google.com/group/algogeeks?hl=en. >>>>> >>>>> >>>> >>>> >>>> -- >>>> <http://thezeitgeistmovement.com>thezeitgeistmovement.com >>>> >>>> -- >>>> You received this message because you are subscribed to the Google >>>> Groups "Algorithm Geeks" group. >>>> To post to this group, send email to <algogeeks@googlegroups.com> >>>> algogeeks@googlegroups.com. >>>> To unsubscribe from this group, send email to >>>> <algogeeks%2bunsubscr...@googlegroups.com> >>>> algogeeks+unsubscr...@googlegroups.com. >>>> For more options, visit this group at >>>> <http://groups.google.com/group/algogeeks?hl=en> >>>> http://groups.google.com/group/algogeeks?hl=en. >>>> >>> >>> >>> >>> -- >>> Regards >>> Gunjan Sharma >>> Chairman IEEE Students Chapter IIT Roorkee >>> B.Tech IV year CSE >>> >>> Contact No- +91 9997767077 >>> >>> -- >>> You received this message because you are subscribed to the Google Groups >>> "Algorithm Geeks" group. >>> To post to this group, send email to <algogeeks@googlegroups.com> >>> algogeeks@googlegroups.com. >>> To unsubscribe from this group, send email to >>> <algogeeks%2bunsubscr...@googlegroups.com> >>> algogeeks+unsubscr...@googlegroups.com. >>> For more options, visit this group at >>> <http://groups.google.com/group/algogeeks?hl=en> >>> http://groups.google.com/group/algogeeks?hl=en. >>> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Regards Gunjan Sharma Chairman IEEE Students Chapter IIT Roorkee B.Tech IV year CSE Contact No- +91 9997767077 -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. 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