Folks, here is an interesting puzzle:
A Rubick's Cube has owl heads on it, which can be misoriented. How many (times) MORE combinations are there of this cube vs. one that has blank stickers? the major difference between the cube with owl's heads and the one without is you might have the heads in 4 different directions depends on how you rotate the cube. Here is what i have: I figured since the problem is asking "how many times", it's asking the relation between two cases. I also realized that the only the axis/ middle piece of the side matters and everything else is fixed because you can only rotate the edges to make the direction of the middle piece changing relatively. Let's say the number of combination of the cube without heads is N. I am thinking since you have 4 possible directions and Y middle pieces and since the pieces are independent, wouldn't that be 4^Y*N combination of the one with heads, which means 4^Y times more than the one without? What do you think? -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
