I don't there is any algorithm for this..

The recursive seems to the best approach for this.
does anyone know if there is any better approach available?


On Apr 12, 4:45 pm, Subhransu <subhransu.panigr...@gmail.com> wrote:
> @baghel: The method returns the desire output.
>
> But looking for some algo which can do the same.
>
> *Subhransu Panigrahi
> *
> *Mobile:* *+91-9840931538*
>  *Email:* subhransu.panigr...@gmail.com
>
>
>
> On Tue, Apr 12, 2011 at 12:08 AM, baghel <anant.bag...@gmail.com> wrote:
> > This solution is incorrect.you are only considering ordered
> > permutations of all the rotations of the list ignoring random
> > permutations.
> > for eg in abcd you are missing random permutation like acbd.
> > here we need implementation of next_permutation() function of c++.
> > this <http://wordaligned.org/articles/next-permutation> might be
> > helpful.
> > Happy coding
>
> > On Apr 9, 12:13 am, Manish Pathak <pathak....@gmail.com> wrote:
> > >  #include <stdio.h>
> > > #include <string.h>
> > > #include <stdlib.h>
> > > int fact(int n);
> > > void main()
> > > {
> > > char a[20],st_char;
> > > static int i,j,k,n,ctr,main_ctr;
> > > printf("Enter the string : ");
> > > //gets(a);
> > > scanf("%s",a);
>
> > > n=strlen(a);
>
> > > if(n<=1)
> > > {
> > > printf("please enter a valid string ");
> > > exit(0);
>
> > > }
>
> > > //label :
> > > while(main_ctr<n)      //loop till length
> > > {
> > > for(i=0;i<=n-2;++i)    //loop to print first character of string ex
> > abc,acb
> > > {
> > > ctr=0;
> > > printf("\n");
> > > printf("%c",a[0]);
> > >     for(j=i+1;j<=n-1;j++)    //take
> > >     {
> > >         printf("%c",a[j]);
> > >         ctr++;
> > >     }
>
> > >     if(ctr!=n-1)
> > >     {
> > >         for(k=1;k<=i;k++)//  print characters that left in above loop ex
> > > from above i=2 print a[0], then j=3 print a[3], means to print a[1] and
> > a[2]
>
> > >         {
> > >         printf("%c",a[k]);
> > >         ctr++;
> > >         }
> > >     }
>
> > > }
>
> > > st_char=a[0];        //ex for abc string this change as a[0]=b;
> > > for(i=0;i<=n-2;i++)    //a[1]=c;
> > >     a[i]=a[i+1];    //a[2]=a;
>
> > > a[n-1]=st_char;
>
> > > main_ctr++;}
>
> > > printf("\n>>>>>Designed by Manish Pathak<<<<<<<< ");
>
> > > }
>
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