int main()
{
int n=60;
double b;
b=n*0.2;
if((b-floor(b))==0)
print " number is divisible by 5";
else
print " number is not divisible by 5";
}
this code works fine
________________________________
From: venkatesan B <venkat_b_engin...@yahoo.co.in>
To: "algogeeks@googlegroups.com" <algogeeks@googlegroups.com>
Sent: Thursday, 5 May 2011 7:12 AM
Subject: Re: [algogeeks] Divisibility by five
b=n*0.2;
if((b-floor(b))==0)
print " number is divisible by 5";
else
print " number is not divisible by 5";
________________________________
From: Umer Farooq <the.um...@gmail.com>
To: algogeeks@googlegroups.com
Sent: Tuesday, 3 May 2011 10:27 AM
Subject: Re: [algogeeks] Divisibility by five
public static isDivisibleByFive(int input)
{String str_input = String.valueof(input); // convert initial int to string.
if ((str_input.charat(str_input.length()-1) == '5') ||
(str_input.charat(str_input.length()-1) == '0') // check if the last character
is 0 or 5
.... return true;
return false;
}
u can try something like this ...
On Tue, May 3, 2011 at 9:25 AM, Dave <dave_and_da...@juno.com> wrote:
Given an integer n, give an O(log n) algorithm to determine if n is
>divisible by 5 without using division or mod.
>
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