@Piyush: I don't think 1010 (and any even number) will be a binary palindrome (Unless u allow single leading zero)...(Either you allow all or allow none) If its not so what about 1001 then ? Whether it will be a palindrome or not ?[?]
Don't you think, it isn't possible to do this in less than O(n) as we have to look at each bit at least once to confirm that given binary number is palindrome ? If O(n) is permitted then Logic used in immanuel's solution looks correct to me.. Any1 having other logic which may have less comparisons ?? -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
<<363.gif>>