Actually
A(int *m=0*)
> {
> a=m;
> }
> not
> A*(int m*) {
> a = m;
> }
>
means m has a default value of 0 ie this value will be used if no parameter
is given . So when you pass it a parameter default value is simply ignored.
On Wed, May 25, 2011 at 12:15 PM, Balaji S <balaji.ceg...@gmail.com> wrote:
> ya.. thanks :) it works. but.. we are initializing m to 0 in everycall
> ryt.. ? then how does 1,2,3,....is initialized??
>
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Thanks and Regards ,
Gaurav Saxena
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