how about this case:

 9, 100 -> 9100
100 9
9100

 2, 3, 9, 78 -->
 78 9 3 2
9 78 3 2

I guess solution should be:-
sort the array of numbers in an ascending order and then check for the first
element in the array, if there is any other element greater than it, shift
all the elements one right and place that element in the left most space.


On Fri, May 27, 2011 at 9:37 AM, wujin chen <wujinchen...@gmail.com> wrote:

> @Piyush, how to deal with this case :100 , 10
>
>
> 2011/5/27 Piyush Sinha <ecstasy.piy...@gmail.com>
>
>> we can work out if we sort according to the leftmost integer
>>
>> On 5/27/11, adityasir...@gmail.com <adityasir...@gmail.com> wrote:
>> > are you kidding me. Just simple sort wont work.
>> >
>> > On Fri, May 27, 2011 at 9:31 AM, radha krishnan <
>> > radhakrishnance...@gmail.com> wrote:
>> >
>> >> sort :)
>> >>
>> >>
>> >> On Fri, May 27, 2011 at 6:57 PM, ross <jagadish1...@gmail.com> wrote:
>> >>
>> >>> Hi all,
>> >>>
>> >>> Given an array of elements find the largest possible number that can
>> >>> be formed by using the elements of the array.
>> >>>
>> >>> eg: 10 9
>> >>> ans: 910
>> >>>
>> >>> 2 3 5 78
>> >>>
>> >>> ans: 78532
>> >>>
>> >>> 100 9
>> >>>
>> >>> ans: 9100
>> >>>
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>> *Piyush Sinha*
>> *IIIT, Allahabad*
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