how about adding zeroes at the end of integers to make to equal to the
integer with maximum number of digits and sort them...

ex-
101 10

adding zeroes..
101 100

sort 100 101

therefore make number as 10110

100 1

adding zeroes
100 100

therefore number is 1100

I am not sure of the method.....if there is any counter case please do
suggest...

On 5/27/11, wujin chen <wujinchen...@gmail.com> wrote:
> @radha,  i think your solution is wrong.
> for this case: 101,10
> in your solution , the ans is 10101,but the max ans is 10110.
>
> 2011/5/27 radha krishnan <radhakrishnance...@gmail.com>
>
>> 10100 is max ans
>> okay
>> convert the numbers to strings and sort based on the first character
>> !!!!!!!
>> if equal do that recursively  and then if length is less give that
>> preference !!
>> i think this solution ..
>> may be this is wrong !!
>>
>> On Fri, May 27, 2011 at 7:07 PM, wujin chen <wujinchen...@gmail.com>wrote:
>>
>>> @Piyush, how to deal with this case :100 , 10
>>>
>>>
>>> 2011/5/27 Piyush Sinha <ecstasy.piy...@gmail.com>
>>>
>>>> we can work out if we sort according to the leftmost integer
>>>>
>>>> On 5/27/11, adityasir...@gmail.com <adityasir...@gmail.com> wrote:
>>>> > are you kidding me. Just simple sort wont work.
>>>> >
>>>> > On Fri, May 27, 2011 at 9:31 AM, radha krishnan <
>>>> > radhakrishnance...@gmail.com> wrote:
>>>> >
>>>> >> sort :)
>>>> >>
>>>> >>
>>>> >> On Fri, May 27, 2011 at 6:57 PM, ross <jagadish1...@gmail.com> wrote:
>>>> >>
>>>> >>> Hi all,
>>>> >>>
>>>> >>> Given an array of elements find the largest possible number that can
>>>> >>> be formed by using the elements of the array.
>>>> >>>
>>>> >>> eg: 10 9
>>>> >>> ans: 910
>>>> >>>
>>>> >>> 2 3 5 78
>>>> >>>
>>>> >>> ans: 78532
>>>> >>>
>>>> >>> 100 9
>>>> >>>
>>>> >>> ans: 9100
>>>> >>>
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