Okay, i thought it this way: iterate through the whole matrix, and
take the value  as a "key" to a hash table. and the value
corresponding to the key would be the "count". increment the count
everytime you encounter the same key. it is very easy to implement
this in python (using dictionary) but i am not sure what will be the
most efficient data structure to implement this in c/c++.

Vishal

On Mon, May 30, 2011 at 10:31 AM, ross <jagadish1...@gmail.com> wrote:
> @vishal
> Hi,
> I do not get you.
> Can you please elaborate a little more how you ll use hash?
>
> On May 30, 8:50 am, Vishal Thanki <vishaltha...@gmail.com> wrote:
>> what about using a hash function?
>>
>>
>>
>>
>>
>>
>>
>> On Mon, May 30, 2011 at 10:18 AM, ross <jagadish1...@gmail.com> wrote:
>> > Given a matrix, you need to find the number of blocks in it.
>> > A block has the same numbers.
>> > EG:
>> > 1 1 3
>> > 1 2 3
>> > 2 2 4
>> > has 4 blocks namely,
>> > 1 1
>> > 1
>> >   2
>> > 2 2
>>
>> > 3
>> > 3
>>
>> > 4
>>
>> > 1 2 3
>> > 4 5 6
>> > 7 8 9
>> > has 9 blocks
>>
>> > 1 1 1
>> > 1 1 3
>> > 4 4 5
>> > has 4 blocks,
>> > 1 1 1
>> > 1 1
>>
>> > 3
>>
>> > 5
>>
>> > 4 4
>>
>> > I used an algorithm as follows,
>> > for each element[i,j] in the matrix,
>> >   enqueue adjacent indices into a queue if they contain the same
>> > element.
>> >  else
>> > incremt blockcount;
>>
>> > return blockcount;
>>
>> > But, this complexity is O(n^3) any better solution exists?
>>
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