i think solution would be like this

eg:
A : 1 2 3 B: 0 1.5 4 5 9
Output:
A can contain any combination of nos 0,1,1.5
and B should contain 2 3 4 5 9 (in any order.)

this example is given by ROSS itself.

so sravanreddy solution is right , correct me if i'm wrong.

On Jun 3, 8:07 pm, bittu <shashank7andr...@gmail.com> wrote:
> @sravanreddy...logical bugs  if A is size of n & B is size m from your
> example  assuming n<m  so if you want smallest m elements in A then u
> only capacity of n elements & didn't allocate memory so these elements
> initialized by INT_MIN for m-n nodes so thatarrayA can hold m
> smallest elements then what r u swapping u dude..isn't garbage
> value ?? you will get at 1st step only just run it ?? in you algo
> A_End=m-1(which 4th position inArraythat DNE)..?? & also you have to
> free memory for  m-n  inarrayB as it contains n largest elements .
>
> take
> A= 1,2,3 n=3
> B= 0,1,4,5,9 m=5
>
> after allocating memory toArrayA  for  m-n elements A will looks
> likes 1 2 3 INT_Max INT_Max
> now what you wants A should contains m smallest elements & B have n
> largest elements
> so O/P should be  A=1,2,3,1,0 & B=INT_Max,INT_Max,4,5,9 now free
> memory used by 1st elements inarrayB so that A will represent M
> smallest elements & B will have n Largest elements
>
> so that above will work.
>
> Hope I am Correct let me know if any issue with explanation
>
> Thanks
> Shashank>>"The Best Way To Escape From Theproblemis To Solve It"
> CSE,BIT Mesra

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