Ohh. Missed out the nlogn condition you mentioned. It will do but in n^2

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------------------------------
From: D.N.Vishwakarma@IITR
Sent: Thursday, 9 June 2011 4:29 PM
To: algogeeks@googlegroups.com
Subject: Re: [algogeeks] Finding total number of inversions in an array in
O(nlogn) complexity .

how insertion sort will do in O(nlogn)?

On Thu, Jun 9, 2011 at 4:27 PM, Navneet Gupta <navneetn...@gmail.com> wrote:

> Insertion sort also would do.
>
> On Thu, Jun 9, 2011 at 4:22 PM, D.N.Vishwakarma@IITR <deok...@gmail.com>
> wrote:
> > thanx for suggestion
> >
> > On Thu, Jun 9, 2011 at 4:08 PM, sunny agrawal <sunny816.i...@gmail.com>
> > wrote:
> >>
> >> Discussed many times,
> >> 1) add some lines to merge sort
> >> 2) use Binary indexed tree for a faster version (i have not tried but
> get
> >> to know it can be done using binary indexed tree)
> >>
> >> On Thu, Jun 9, 2011 at 4:05 PM, D.N.Vishwakarma@IITR <deok...@gmail.com
> >
> >> wrote:
> >>>
> >>> Inversion means pair(i,j) such that i<j and A[i]>A[j]
> >>>
> >>> --
> >>> With Regards
> >>> Deoki Nandan Vishwakarma
> >>> IITR MCA
> >>>
> >>>
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> >>
> >>
> >>
> >> --
> >> Sunny Aggrawal
> >> B-Tech IV year,CSI
> >> Indian Institute Of Technology,Roorkee
> >>
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> >
> > --
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> > Deoki Nandan Vishwakarma
> > IITR MCA
> >
> >
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> --Navneet
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-- 
**With Regards
Deoki Nandan Vishwakarma
IITR MCA
*
*

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