can anyone explain "Since there
are less than 2^32 numbers in the file there is bound to be one number
in the array that is less than 2^16." in dumanshu's solution.

On Fri, Jun 10, 2011 at 12:39 PM, varun pahwa <varunpahwa2...@gmail.com>wrote:

> @ankit :please explain by taking an example.
>
>
> On Fri, Jun 10, 2011 at 12:13 PM, Vetri Balaji <vetribal...@gmail.com>wrote:
>
>> @ankit: pls explain the time complexity..
>> i dont think its O(log n)
>>
>>
>> On Thu, Jun 9, 2011 at 11:57 PM, ankit sambyal <ankitsamb...@gmail.com>wrote:
>>
>>> @Dumanshu:  In each iteration, we r removing the smallest number. If
>>> at any iteration we can't find the next smallest no., it means that
>>> no. is missing.....
>>>
>>>
>>>
>>> On Thu, Jun 9, 2011 at 10:54 AM, Dumanshu <duman...@gmail.com> wrote:
>>> > hey... we have 300 million (9- digit) numbers. So we have to print a
>>> > number which isn't already there in the file.
>>> > We are not given that number beforehand. You are saying to check "u
>>> > are going to check whether a number N exist ".
>>> >
>>> > On Jun 9, 4:46 pm, radha krishnan <radhakrishnance...@gmail.com>
>>> > wrote:
>>> >> Ma approach is to xor the given number with all numbers in the file !!
>>> >> This takes O(n)
>>> >> I think we cant achieve a complexity <O(n)
>>> >> we have to scan the file at least once
>>> >>
>>> >> Or move to this problem
>>> >> Instead of a file with numbers
>>> >> you have a stream of numbers
>>> >>
>>> >> Create a Trie and insert every number from the stream by reversing the
>>> >> digits of the number
>>> >> Now u have a Trie (left as 0 bit && right as 1 bit )
>>> >>
>>> >> u are going to check whether a number N exist
>>> >> reverse the bits of N
>>> >> search for appropriate bit in the Trie
>>> >> if all bit are matched then there is a number !!
>>> >> else No
>>> >>
>>> >> But Space Complexity Of Trie is high  we need (32 *(O(n)) assuming
>>> each
>>> >> integer is of 32 bits
>>> >>
>>> >>
>>> >>
>>> >>
>>> >>
>>> >>
>>> >>
>>> >> On Thu, Jun 9, 2011 at 4:54 PM, Dumanshu <duman...@gmail.com> wrote:
>>> >> > Given a file containing roughly 300 million social security
>>> numbers(9-
>>> >> > digit numbers) find a 9-digit number that isnt there in the file.
>>> You
>>> >> > have unlimited drive space but only 2mb of RAM.
>>> >>
>>> >> > Solution is as follows:
>>> >> > In the first step, we build an array of 2^16 integers that is
>>> >> > initialized to 0 and for every number in the file we take its 16
>>> most
>>> >> > significant
>>> >> > bit to index into this array and increment that number. Since there
>>> >> > are less than 2^32 numbers in the file there is bound to be one
>>> number
>>> >> > in the array that is less than 2^16 . This tells us that there is at
>>> >> > least one number missing among the possible numbers with those upper
>>> >> > bits. In the second pass, we can focus only on the numbers that
>>> match
>>> >> > this criterion and use a bit-vector of size 2^16 to identify one of
>>> >> > the missing numbers.
>>> >>
>>> >> > Someone plz explain this solution( may be using some small values
>>> >> > numbers) or suggest another approach.
>>> >>
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>
>
>
> --
> Varun Pahwa
> B.Tech (IT)
> 7th Sem.
> Indian Institute of Information Technology Allahabad.
> Ph : 09793899112 ,08011820777
> Official Email :: rit2008...@iiita.ac.in
> Another Email :: varunpahwa.ii...@gmail.com
>
> People who fail to plan are those who plan to fail.
>
>


-- 
Varun Pahwa
B.Tech (IT)
7th Sem.
Indian Institute of Information Technology Allahabad.
Ph : 09793899112 ,08011820777
Official Email :: rit2008...@iiita.ac.in
Another Email :: varunpahwa.ii...@gmail.com

People who fail to plan are those who plan to fail.

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