thats why i mentioned x OR z and i m considering parent pointer :)
without parent pointer both solutions will be O(n) :)

On Fri, Jun 10, 2011 at 3:02 PM, Harshal <hc4...@gmail.com> wrote:

> @Sunny
> I am assuming that the tree is rooted. There is no 'parent' pointer.
>                   A
>               /      \
>            B         C*
>           /               \
>        D*                 F*
>                           /  \
>                         J      K
>                        /  \
>                            M*
>
> suppose x=D, y=C, z=F
> According to you, finding the lca of x and z=> A
> Now y lies on path from lca to z, but it doesn't lie on path from x to z.
> Am I missing something?
>
>
> On Fri, Jun 10, 2011 at 2:50 PM, sunny agrawal <sunny816.i...@gmail.com>wrote:
>
>> but that will be O(n) i think
>>
>>
>> On Fri, Jun 10, 2011 at 2:38 PM, Harshal <hc4...@gmail.com> wrote:
>>
>>> can be solved using dfs.
>>>
>>>
>>> On Fri, Jun 10, 2011 at 2:27 PM, sunny agrawal 
>>> <sunny816.i...@gmail.com>wrote:
>>>
>>>> find common Ancestor of both. see if y lies on path from x or z to this
>>>> ancestor
>>>> O(lgn)
>>>>
>>>>
>>>> On Fri, Jun 10, 2011 at 1:20 PM, aanchal goyal <
>>>> goyal.aanch...@gmail.com> wrote:
>>>>
>>>>> There is a binary tree(Not a BST) in which you are given three nodes
>>>>> x,y,z .Write a function which finds whether y lies in the path b/w x
>>>>> and z.
>>>>>
>>>>> --
>>>>> Regards,*
>>>>> Aanchal Goyal*.
>>>>>
>>>>>  --
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>>>>
>>>>
>>>>
>>>> --
>>>> Sunny Aggrawal
>>>> B-Tech IV year,CSI
>>>> Indian Institute Of Technology,Roorkee
>>>>
>>>>
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>>>
>>>
>>> --
>>> Harshal Choudhary,
>>> III Year B.Tech CSE,
>>> NIT Surathkal, Karnataka, India.
>>>
>>>
>>>
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>>
>>
>>
>> --
>> Sunny Aggrawal
>> B-Tech IV year,CSI
>> Indian Institute Of Technology,Roorkee
>>
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>
>
>
> --
> Harshal Choudhary,
> III Year B.Tech CSE,
> NIT Surathkal, Karnataka, India.
>
>
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>



-- 
Sunny Aggrawal
B-Tech IV year,CSI
Indian Institute Of Technology,Roorkee

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