In 1st program, 2nd printf requires one more argument. And basically
%a is used for printing a double value in hex. see "man 3 printf".
On Sat, Jun 11, 2011 at 5:29 PM, nicks <crazy.logic.k...@gmail.com> wrote:
> Hello friends..plz help me in understanding the following C Output
>
> first one is --
>
> #include<stdio.h>
> #include<conio.h>
> main()
> {
> int a=5;
> printf("a=%d\n",a);
> printf("%a=%d",a);
> getch();
> }
> OUTPUT -
> a=5
> 0x1.2ff380p-1021=4199082
>
>
> and the other one is --
>
> #include<stdio.H>
> # include <conio.h>
> int i=2;
> main()
> {
> void add();
> add(i++,--i);
> printf("\ni=%d \n",i);system("pause");
> }
> void add(int a ,int b)
> {
> printf("\na=%d b=%d",a,b);
> }
>
> OUTPUT -
> a=1 b=1
> i=2
>
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