I think BFS will do That isn't it.??  lets say we have starting node
v  & wants to find shortest path e.g leaf at lowest height say this
node u so when you will do BFS each level will represent the shortest
path between two nodes. shortest path=min dist(V,U)

DS Used Queue
Time Complexity O(N)


Correct me if anything wrong


Shashank
Computer Science
CSE,BIT Mesra

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