the arguments are passed from right to left in a function...
initially ptr is pointing to location of 98 (i =1)
the last argument ++ptr makes it point to 99 therefore output of *e = 99
the second last argument passes pointer to 99 only and then
increments its location to i=3 i.e 100...therefore output of *d = 99
and *c = 100
the second argument is pointing to location of i=3 only and then
decrements to point to location of i=2..therefore output of *a =100
and *b =100..
hope you understood the sequence of outputs...:) :)
On 6/22/11, Piyush Sinha <ecstasy.piy...@gmail.com> wrote:
> r u sure the last output is also 100..for me its coming 99
>
> On 6/22/11, udit sharma <sharmaudit...@gmail.com> wrote:
>> #include<stdio.h>
>> int main()
>> {
>> void print(int *,int *,int *,int *,int *);
>> static int arr[]={97,98,99,100,101,102,103,104};
>> int *ptr=arr+1;
>> print(++ptr,ptr--,ptr,ptr++,++ptr);
>> return 0;
>> }
>> void print(int *a,int *b,int *c,int *d,int *e)
>> {
>> printf("%d\t%d\t%d\t%d\t%d\n",*a,*b,*c,*d,*e);
>> }
>>
>> Why the output is:
>> 100 100 100 99 100
>>
>>
>> --
>> Regards
>> UDIT
>> DU- MCA
>>
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>
>
> --
> *Piyush Sinha*
> *IIIT, Allahabad*
> *+91-8792136657*
> *+91-7483122727*
> *https://www.facebook.com/profile.php?id=100000655377926 *
>
--
*Piyush Sinha*
*IIIT, Allahabad*
*+91-8792136657*
*+91-7483122727*
*https://www.facebook.com/profile.php?id=100000655377926 *
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