#include<stdio.h>
main()
{
long double *var;
printf("%d",(char*)(var+1)-(char*)var);
return 0;
}
This also may be the solution... by taking the pointer of that variable...
On Fri, Jun 24, 2011 at 2:09 AM, vaibhav shukla <vaibhav200...@gmail.com>wrote:
> here is the generalized way
>
>
> #include<stdio.h>
> #define SIZEOF(var) (size_t)(&var+1) - (size_t)(&var)
> main()
> {
> double x;
> printf("The size of x is %d\n",SIZEOF(x));
> return 0;
> }
>
> On Fri, Jun 24, 2011 at 1:35 AM, Anika Jain <anika.jai...@gmail.com>wrote:
>
>> #include<stdio.h>
>>
>> int main()
>> {
>> char x='9',size=0,count;
>> while(x)
>> {
>> x = x<<1;
>> count++;
>> if((count=count%8)==0)
>> {
>> size++;
>> }
>> }
>> printf("%d\n",size);
>> return 0;
>> }
>>
>> this code i tried to find size of a variable without using sizeof.. but
>> its only for ints and chars... not general.. does anybody hava a general
>> answer??
>>
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>
>
>
> --
> best wishes!!
> Vaibhav Shukla
> DU-MCA
>
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--
Dileep Kumar
B.Tech 3rd Yr
MNNIT, Allahabad
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