@sagar : it works perfectly fine.
On Tue, Jun 28, 2011 at 3:29 PM, sagar pareek <sagarpar...@gmail.com> wrote:
> Check out my solution above :)
> Its reversing the string
>
>
> On Tue, Jun 28, 2011 at 1:56 PM, shady <sinv...@gmail.com> wrote:
>
>> no, you arent actually reversing anything, you are just printing.
>>
>>
>> On Tue, Jun 28, 2011 at 11:40 AM, Kamakshii Aggarwal <
>> kamakshi...@gmail.com> wrote:
>>
>>>
>>> #include <stdio.h>
>>> #include <stdlib.h>
>>>
>>> void revers(char *s)
>>> {
>>>
>>> if(*s)
>>> {
>>> revers(++s);
>>> s--;
>>> printf("%c ",*s);
>>> }
>>>
>>> }
>>>
>>> int main(int argc, char *argv[])
>>> {
>>> char arr[]="string";
>>> revers(arr);
>>>
>>> system("PAUSE");
>>> return 0;
>>> }
>>>
>>> acording to above given definition of temporary variable will the above
>>> code also work for this question???
>>>
>>> On Mon, Jun 27, 2011 at 11:56 PM, Swathi <chukka.swa...@gmail.com>wrote:
>>>
>>>> it works perfectly
>>>>
>>>>
>>>> On Mon, Jun 27, 2011 at 11:53 PM, hary rathor
>>>> <harry.rat...@gmail.com>wrote:
>>>>
>>>>> this solution according to sameer statement solution if there is any
>>>>> problem then pls tell me . here string or char is not being
>>>>> store anywhere
>>>>>
>>>>> char * reverse(char *str,int i ,int j)
>>>>> {
>>>>> while(i<j)
>>>>> {
>>>>>
>>>>> str[i]=str[i]^str[j];
>>>>> str[j]=str[i]^str[j];
>>>>> str[i]=str[i]^str[j];
>>>>> i++;j--;
>>>>> }
>>>>> return str;
>>>>> }
>>>>>
>>>>> int main ()
>>>>> {
>>>>> char str[]="harish";
>>>>> printf("%s",reverse(str,0,sizeof(str)-2));
>>>>> return 0;
>>>>>
>>>>> }
>>>>>
>>>>>
>>>>> --
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>>>>
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>>>
>>>
>>>
>>> --
>>> Regards,
>>> Kamakshi
>>> kamakshi...@gmail.com
>>>
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>>
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>
>
>
> --
> **Regards
> SAGAR PAREEK
> COMPUTER SCIENCE AND ENGINEERING
> NIT ALLAHABAD
>
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