There is a very simple solution to this problem, Pseudo Code follows:
Inputs: str - string, c1,c2 are characters.
*MinDistance(str, c1, c2):
initialize RightMostIndex[127] with all entries as -1
initialize curMin as Len(str)+1
For i = 0 to Len(str) - 1
if str[i] is same c1 then
if RightMostIndex[c2] != -1 then
curMin = minimum(curMin, i - RightMostIndex[c2])
Set RightMostIndex[c1] = i
otherwise if str[i] is same as c2 then
if RightMostIndex[c1] != -1 then
CurMin = minimum(curMin, i - RightMostIndex[c1])
Set RightMostIndex[c2] = i
Output CurMin*
C++ implementation at http://ideone.com/11H2z
Thanks,
Rizwan.
On Tue, Jun 28, 2011 at 3:54 PM, Gaurav Saxena <grvsaxena...@gmail.com>
wrote:
> What is the problem with sunny's solution ??
>
> On Mon, Jun 20, 2011 at 9:31 AM, RAJAT kumar singh <
rajat123si...@gmail.com>
> wrote:
>>
>> #include<stdio.h>
>> #include<math.h>
>> char
>>
s[]={'a','x','x','b','a','b','x','x','x','x','x','a','b','a','x','x','b',};
>>
>>
>> int minimum(char,char,int );
>> int main()
>> {
>>
>> int i=minimum('a','b',17);
>> printf("%d",i);
>> }
>>
>>
>> int minimum(char a ,char b,int n)
>> {
>> int i=0;
>> int lindex=-1,rindex=-1,min;
>>
>> min=n;
>> while(i<n)
>> {
>>
>>
>>
>>
>> if(s[i]==a)
>> {
>> lindex=i;
>> if(rindex!=-1)
>> {
>> min=mini(min,abs(lindex-rindex));
>> }
>> }
>>
>> else if(s[i]==b)
>> {
>> rindex=i;
>> if(lindex!=-1)
>> {
>> min=mini(min,abs(lindex-rindex));
>> }
>>
>>
>>
>> }
>>
>>
>> i++;
>> }
>>
>> return min;
>> }
>>
>>
>> int mini(int a,int b)
>> {
>>
>> if(a>b)
>> return b;
>> else
>> return a;
>>
>>
>> }
>>
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>
>
>
> --
> Thanks and Regards ,
> Gaurav Saxena
>
> --
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--
Thanks and regards
Rizwan A Hudda
http://sites.google.com/site/rizwanhudda2
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