Sorry dave, your solution works.
Thanks for the answer, What I was assuming to be a Counting sort was a
variant of it
for integers.

On Thu, Jun 30, 2011 at 7:56 AM, Dave <dave_and_da...@juno.com> wrote:

> @Rizwan: I don't see the problem. Initialize an array of counters, one
> for each possible last character, to zero. If there are no
> restrictions on the last character, use an array of 256 counters.
> Then, for each string, increment the counter corresponding to the last
> character of the string by the length of the string (or 1 + the length
> of the string if you want to store the null byte). After all of the
> strings are processed, compute the running sum of the counters to get
> the position in the output array of the first entry for each last
> character. Then copy the strings into the output array at the position
> indicated by the appropriate counter, and increment that counter by
> the number of characters copied.
>
> Why doesn't this work? And isn't it a counting sort?
>
> Dave
>
> On Jun 29, 7:05 pm, rizwan hudda <rizwanhu...@gmail.com> wrote:
> > @Dave: Think of it again counting sort won't work, If you are just
> > considering the last character as
> > the even though key is just last character, the value is the whole
> string..
> >
> >
> >
> >
> >
> > On Tue, Jun 28, 2011 at 1:53 PM, juver++ <avpostni...@gmail.com> wrote:
> > > List[letter] - linked list of all words with the last character as
> letter.
> > > Then iterate over all letters and concatenate lists.
> >
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> > Rizwan A Huddahttp://sites.google.com/site/rizwanhudda2- Hide quoted
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-- 
Thanks and regards
Rizwan A Hudda
http://sites.google.com/site/rizwanhudda2

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