l = 8 1 0 0 0 k = 6 0 1 1 0 xor 1 1 1 0 difference = 2
l = 16 1 0 0 0 0 k = 4 0 0 1 0 0 xor On Sat, Jul 2, 2011 at 2:09 PM, sunny agrawal <sunny816.i...@gmail.com>wrote: > yes i have written that only > difference between indexes of first set bit and last set bit > > On Sat, Jul 2, 2011 at 2:08 PM, cegprakash <cegprak...@gmail.com> wrote: > >> whats mean by first set bit and last set bit? do you simply mean the >> index of first and last bit? >> >> On Jul 2, 1:25 pm, sunny agrawal <sunny816.i...@gmail.com> wrote: >> > xor the length of the rope with the required length and difference >> between >> > the indexes of first set and last set bit *may* be the answer !! >> > >> > >> > >> > On Sat, Jul 2, 2011 at 1:46 PM, cegprakash <cegprak...@gmail.com> >> wrote: >> > > nope >> > >> > > On Jul 2, 1:14 pm, keyan karthi <keyankarthi1...@gmail.com> wrote: >> > > > yup :) >> > >> > > > On Sat, Jul 2, 2011 at 1:38 PM, Shalini Sah < >> > > shalinisah.luv4cod...@gmail.com >> > >> > > > > wrote: >> > > > > i guess the no. of 1s in the binary representation of the number >> is the >> > > > > answer..for 6 its 2... >> > >> > > > > On Sat, Jul 2, 2011 at 1:32 PM, cegprakash <cegprak...@gmail.com> >> > > wrote: >> > >> > > > >> the length of the rope is l units. >> > > > >> I can only cut any rope into two halves. >> > >> > > > >> for example if the length of the rope is 8 and we need a length >> of >> > > > >> rope 6 >> > >> > > > >> we first cut into two halves and we get 4, 4 >> > > > >> now we cut any of the half again and we get 4,2,2 >> > >> > > > >> now we can merge 4 and 2 and form a rope of length 6. >> > >> > > > >> in this example we need a minimum of 2 cuts to get the length of >> rope >> > > > >> 6 from 8 >> > >> > > > >> assume that l is always a power of 2 and we need always a even >> length >> > > > >> of rope from it how to find the number of minimum cuts needed to >> get >> > > > >> the new rope?. >> > >> > > > >> -- >> > > > >> You received this message because you are subscribed to the >> Google >> > > Groups >> > > > >> "Algorithm Geeks" group. >> > > > >> To post to this group, send email to algogeeks@googlegroups.com. >> > > > >> To unsubscribe from this group, send email to >> > > > >> algogeeks+unsubscr...@googlegroups.com. >> > > > >> For more options, visit this group at >> > > > >>http://groups.google.com/group/algogeeks?hl=en. >> > >> > > > > -- >> > > > > You received this message because you are subscribed to the Google >> > > Groups >> > > > > "Algorithm Geeks" group. >> > > > > To post to this group, send email to algogeeks@googlegroups.com. >> > > > > To unsubscribe from this group, send email to >> > > > > algogeeks+unsubscr...@googlegroups.com. >> > > > > For more options, visit this group at >> > > > >http://groups.google.com/group/algogeeks?hl=en. >> > >> > > -- >> > > You received this message because you are subscribed to the Google >> Groups >> > > "Algorithm Geeks" group. >> > > To post to this group, send email to algogeeks@googlegroups.com. >> > > To unsubscribe from this group, send email to >> > > algogeeks+unsubscr...@googlegroups.com. >> > > For more options, visit this group at >> > >http://groups.google.com/group/algogeeks?hl=en. >> > >> > -- >> > Sunny Aggrawal >> > B-Tech IV year,CSI >> > Indian Institute Of Technology,Roorkee >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> >> > > > -- > Sunny Aggrawal > B-Tech IV year,CSI > Indian Institute Of Technology,Roorkee > > -- Sunny Aggrawal B-Tech IV year,CSI Indian Institute Of Technology,Roorkee -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
