what abt this...
check length of the  array if same then we make a min heap of both the
arrays which can be done in O(n) and call extraxtmin(). in this way we can
find whether they r equal.
othwersie nt equal.

correct me if i am wrong!!

On Mon, Jul 4, 2011 at 4:35 AM, saurabh singh <saurab...@gmail.com> wrote:

> Lets conclude this post.Shall we?
> .An o(n) seems infeasible without any significant extra memory....
> If extra memory is allowed,hash maps can be used to bring it down to
> o(logn).But hash maps would eat up serious memory if numbers occupy a large
> range.
>
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