@piyush : thanks i thot most significant bit was take as fisrt figure .

On Wed, Jul 6, 2011 at 1:03 AM, Piyush Kapoor <pkjee2...@gmail.com> wrote:

> 7 occurs 1 time...
> so 8th digit is 1
>
> On Wed, Jul 6, 2011 at 1:02 AM, aditya kumar <aditya.kumar130...@gmail.com
> > wrote:
>
>> in 70000000 : '0' occurs seven times and rst of the numbers occur zero
>> times. i still dint get where i am wrong . plz explain me .
>>
>>
>> On Wed, Jul 6, 2011 at 12:47 AM, L <prnk.bhatna...@gmail.com> wrote:
>>
>>> @aditya : I am wondering how many times 7 has occurred. Is it 1? Or is
>>> it 0?
>>>
>>> Please take a moment before posting your solution, and think whether
>>> it is write or wrong!
>>>
>>> On Jul 6, 12:11 am, aditya kumar <aditya.kumar130...@gmail.com> wrote:
>>> > Q3. ans:70000000 i guess this is also a correct answer and no unique
>>> soln as
>>> > such
>>> >
>>> > On Wed, Jul 6, 2011 at 12:37 AM, aditya kumar
>>> > <aditya.kumar130...@gmail.com>wrote:
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> > >  boolean palindromeCheck(String string)
>>> > > {
>>> > >  len=string.length();
>>> > > if((string.length()>1))
>>> > > {
>>> > >  if((string.charAt(0)==string.charAt(len-1)))
>>> > > {
>>> > > str="";
>>> > >  str=str+string.substring(1,(len-1));
>>> > > palindromeCheck(str);
>>> > > }
>>> > >  else
>>> > > {
>>> > >  flag=false;
>>> > > }
>>> > >     }
>>> > >  return flag;
>>> > > }
>>> >
>>> > > THis also works fine if you dont want to use pointer
>>> >
>>> > > On Tue, Jul 5, 2011 at 9:37 PM, Azhar Hussain <azhar...@gmail.com>
>>> wrote:
>>> >
>>> > >> For Q4: I think this is the optimal code
>>> >
>>> > >> int recurPalin(char *start, char *end)
>>> > >> {
>>> > >>     if (end < start)
>>> > >>         return true;
>>> >
>>> > >>     if (*start != *end)
>>> > >>         return false;
>>> >
>>> > >>     return recurPalin(start+1, end-1);
>>> > >> }
>>> >
>>> > >> -
>>> > >> Azhar.
>>> >
>>> > >> On Tue, Jul 5, 2011 at 12:21 PM, vikas <mehta...@gmail.com> wrote:
>>> >
>>> > >>> My program for Q4.
>>> > >>>  // recursively find if a given string is palindrome
>>> > >>>         bool IsPalindrome(string s, int start, int start2, bool
>>> flag)
>>> > >>>         {
>>> > >>>             bool flag1 = flag;
>>> > >>>             if (start >= 0 && start2 < (s.Length))
>>> > >>>             {
>>> > >>>                 char c1 = s[start];
>>> > >>>                 char c2 = s[start2];
>>> > >>>                 if (c1.Equals(c2))
>>> > >>>                 {
>>> > >>>                     if (start == 0 && start2 == s.Length - 1) {
>>> flag =
>>> > >>> true; }
>>> > >>>                     if (IsPalindrome(s, start - 1, start2 + 1,
>>> flag))
>>> > >>>                     {
>>> > >>>                         flag1 = true;
>>> > >>>                     }
>>> > >>>                 }
>>> > >>>             }
>>> > >>>             return flag1;
>>> > >>>         }
>>> >
>>> > >>> while calling
>>> > >>>            if (s.Length % 2 != 0)
>>> > >>>             {
>>> > >>>                 p.IsPalindrome(s, s.Length / 2 - 1, s.Length / 2 +
>>> 1,
>>> > >>> false);
>>> > >>>             }
>>> > >>>             else
>>> > >>>             {
>>> > >>>                 p.IsPalindrome(s, s.Length / 2 - 1, s.Length / 2,
>>> false);
>>> >
>>> > >>>             }
>>> >
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>
>
>
> --
> *Regards,*
> *Piyush Kapoor,*
> *CSE-IT-BHU*
>
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