@piyush: No,one can declare the variable of empty struct and access its address via pointer. So, when you are accessing address via pointer means some memory is allocated for that variable. But *sizeof()* operator returns *zero*?? why???
On Wed, Jul 6, 2011 at 10:38 PM, T3rminal <piyush....@gmail.com> wrote: > @ashish > Most probably because empty struct in C have nothing associated with it. > They are as good as nothing. But empty classes in C++ can have member > functions. These functions need to be associated with object, having a > unique address, for that class. And unique address is not possible with > class of size 0 as already explained above. > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To view this discussion on the web visit > https://groups.google.com/d/msg/algogeeks/-/XP8yGGz2YbEJ. > > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- With Regards Ashish Modi 9423721478 -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
