@Anon: Nope. Suppose a=0 and b=2. Then the probability of getting 0 is 1/4, the probability of getting 1 is 1/2, and the probability of getting 2 is 1/4.
Dave On Jul 6, 11:31 pm, anonymous procrastination <opamp1...@gmail.com> wrote: > @surender > Yep, I think the same. > for(i=0;i<(b-a);i++,a+=rand(0,1)); > > Watsay? -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
