Algo :
Given array a[m] and b[2*m]
1. Shift the elements in the array b to the right half. Now the m
elements in the array b are from index m to 2m-1
2. Initialize i (iterator of array a[]) =0
j (iterator of array b[]) = m
k (iterator of the final array which is b[]) = 0
3.
while(1)
{
if(i==m)
break;
else if(j==2m)
{
Copy the remaining elements from array a[] into array b[]
Then break;
}
else
{
if(a[i] < b[j])
b[k++]=a[i++];
else
b[k++]=b[j++];
}
}
Time Complexity : O(m)
Space Complexity : O(1)
On Thu, Jul 7, 2011 at 1:49 PM, sunny agrawal <sunny816.i...@gmail.com> wrote:
> O(m) is always better than O(m^2) :) :P
> Simple merge sort
> hint : start from end of the arrays
>
> select the text in white font to see the hint :)
>
> On Fri, Jul 8, 2011 at 1:56 AM, Dumanshu <duman...@gmail.com> wrote:
>>
>> given two sorted arrays a[m] b[2*m], each contains m elements only.
>> You
>> need to merge those two arrays into second array b[2*m].
>> anything better than O(m^2)????
>>
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>
>
>
> --
> Sunny Aggrawal
> B-Tech IV year,CSI
> Indian Institute Of Technology,Roorkee
>
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