for the first expression. summation (i = 1 to i = n ) on i * i ! gives ((n+1)! - 1). May be this may help in solving the problem. that is 1*1! = 2! - 1. 1*1! + 2*2! = 3! - 1. similarly, 1*1! + 2*2! + 3*3! ... + 10*10! = 11! - 1.
On Sun, Jul 10, 2011 at 10:27 AM, Dave <dave_and_da...@juno.com> wrote: > For the expression, I don't see a simple way. The result is slightly > less than 1. > > For the second problem, 1597 is the only odd prime in the list, so it > could be the odd one out. > > Dave > > On Jul 9, 10:15 pm, Sriganesh Krishnan <2448...@gmail.com> wrote: > > (1*1!+2*2!+3*3!+4*4!....+10*10!)/11! > > ..... > > is there any shortcut methods to solve such problems....? > > > > find the odd one out... > > > > 13700, 1597, 326, 65, 16 , 6 , 2.... > > > > and i have no clue to how to solve the second question!!!! > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- Varun Pahwa B.Tech (IT) 7th Sem. Indian Institute of Information Technology Allahabad. Ph : 09793899112 Official Email :: rit2008...@iiita.ac.in Another Email :: varunpahwa.ii...@gmail.com People who fail to plan are those who plan to fail. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
