@sunny: my algo will give 5 as answer ....and i guess its right... if am
wrong plz explain where and why my logic is wrong

On Sun, Jul 10, 2011 at 5:37 AM, sunny agrawal <sunny816.i...@gmail.com>wrote:

> @Yogesh
> your solution will give maximum Contiguous AP only
> it will fail for the array A[] = {1,2,3,4,5,6,8,10,12,14}
> your algo will give output that there is an Longest AP of 6 elements which
> is wrong
>
> checkout this <http://theory.cs.uiuc.edu/%7Ejeffe/pubs/pdf/arith.pdf> for
> an O(n^2) algorithm
>
>
> On Sun, Jul 10, 2011 at 7:01 PM, Yogesh Yadav <medu...@gmail.com> wrote:
>
>> @raj :
>>
>> array a[]= 2,3,5,6,7,8,10,12
>> diff[]=       1,2,1,1,1,2,2
>>
>> maxcount=tempcount=1   // because am not takin in consideration of 0th
>> index value of diff[]
>>
>> now in for loop
>> for j=1
>> check diff[j]==diff[j-1] //not equal
>> so check tempcount>maxcount or not  //its also not
>> so maxcount remains same and tempcount becomes 1 again
>>
>> now for j=2
>>
>> check diff[j]==diff[j-1] //not equal
>> so check tempcount>maxcount or not  //its also not
>> so maxcount remains same and tempcount becomes 1 again
>>
>> now for j=3
>>
>> check diff[j]==diff[j-1] // equal
>> so tempcount++;
>>
>> and so on....
>>
>>
>>
>>
>> On Sun, Jul 10, 2011 at 5:23 AM, raj singh <ankurkaku...@gmail.com>wrote:
>>
>>> @yogesh- can u explain with an example pls?
>>>
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>
>
>
> --
> Sunny Aggrawal
> B-Tech IV year,CSI
> Indian Institute Of Technology,Roorkee
>
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