Got it Thanks .....
On Jul 10, 10:40 pm, vaibhav shukla <vaibhav200...@gmail.com> wrote:
> associativity comes into play when operators are of same precedence.
>
> On Sun, Jul 10, 2011 at 11:08 PM, vaibhav shukla
> <vaibhav200...@gmail.com>wrote:
>
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> > && has higher precedence than ||
> > the expression is evaluated as
> > z=j || ( k && i );
> > hence the output i.e 1 ;)
>
> > On Sun, Jul 10, 2011 at 11:06 PM, rShetty <rajeevr...@gmail.com> wrote:
>
> >> #include<stdio.h>
> >> int main()
> >> {
> >> int i=0,j=1,k=1,z=0;
> >> z = j || k && i ;
> >> printf("%d",z);
> >> return 0;
> >> }
>
> >> The output is 1 for the above program .
>
> >> But according to associativity of logical operators , the evaluation
> >> should be from left to right , But is it taking from right to left ?
> >> What is the exact concept for the program behavior above?
>
> >> --
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>
> > --
> > best wishes!!
> > Vaibhav Shukla
> > DU-MCA
>
> --
> best wishes!!
> Vaibhav Shukla
> DU-MCA
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