@Harsha, Yes!, the bottom up approach is the best and avoids lot of
repeated calculations.

Cheers,
Vignesh

On Jul 11, 10:13 am, Harshal <hc4...@gmail.com> wrote:
> @vigneshr, no your method is not that efficient since you will be calling
> IsBST for a node many times in the process. It will be O(nlogn) assuming
> complete Binary Tree, Sunny's algorithm runs in O(n) time.
>
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> On Sun, Jul 10, 2011 at 11:25 PM, vigneshr <rvignesh1...@gmail.com> wrote:
> > I donno if my idea is efficient.
> > I'll do a breath-first traversal and check IsBST on each node(modified
> > to also get the count of nodes)
> > So at each level, the largest BST is kept track of and end of the
> > level, the largest subtree can be returned.
> > If there is no BST at that level go down one level more.
>
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> Best Regards,
> Harshal Choudhary
> 7th Semester, CSE Dept.
> NIT Surathkal, India.
> "The road to knowledge runs through the land of confusion."
>
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