z = x + (-y) :)
On Tue, Jul 12, 2011 at 10:58 AM, Sunny T <sunny.1...@gmail.com> wrote: > i would say.. implementing subtraction using division and modulus is more > costly and complicated. bit manipulation is the fastest among all > these techniques..... > x=a-b = (a/b)*b + a%b > .here u are performing... totally 4 operations..1 division,1 > multiplication,1 modulus and 1 addition.. > > it can be easily done by... > > x=a+(~b+1). this solution takes less number of operation than > ur solution and involve less costly operators. > > On Tue, Jul 12, 2011 at 10:29 AM, Dave <dave_and_da...@juno.com> wrote: >> >> @Chandy: Let a = 5 and b = 3. Then x = 5 - 3 = (5/3)*3 + 5%3 = 1*3 + 2 >> = 5. Check? >> >> Dave >> >> On Jul 11, 11:38 pm, chandy jose paul <jpchaa...@gmail.com> wrote: >> > Y are u guys complicating things.Its as simple as this >> > >> > x=a-b = (a/b)*b + a%b >> > >> > >> > >> > On Tue, Jul 12, 2011 at 1:18 AM, Dave <dave_and_da...@juno.com> wrote: >> > > @Aditya: Since 124 is a 3-digit number, I think it would make more >> > > sense to use the 3-digit 10's complement of 46, i.e., 954. Then 124 + >> > > 954 = 1078. Since we are working in 3-digit numbers, the 1 represents >> > > an overflow, which you ignore. Thus, the answer is 78. >> > >> > > Dave >> > >> > > On Jul 11, 2:42 pm, aditya pratap <contacttoadity...@gmail.com> wrote: >> > > > suppose u want to do 124 - 46 >> > >> > > > step1 : write 10's complement of 46 i.e. 53 (9's complement) +1 = 54 >> > > > step2: add 124 + 54 = 178 >> > > > step3: neglect 1 from 178 and answer will be 78. >> > >> > > > correct me if i am wrong. >> > >> > > > On Tue, Jul 12, 2011 at 12:54 AM, Anika Jain >> > > > <anika.jai...@gmail.com> >> > > wrote: >> > > > > how to do subtraction of two integers widout using subtractn?? >> > >> > > > > -- >> > > > > You received this message because you are subscribed to the Google >> > > Groups >> > > > > "Algorithm Geeks" group. >> > > > > To post to this group, send email to algogeeks@googlegroups.com. >> > > > > To unsubscribe from this group, send email to >> > > > > algogeeks+unsubscr...@googlegroups.com. >> > > > > For more options, visit this group at >> > > > >http://groups.google.com/group/algogeeks?hl=en. >> > >> > > > -- >> > > > Regards >> > > > Aditya Pratap >> > > > MCA II >> > >> > > -- >> > > You received this message because you are subscribed to the Google >> > > Groups >> > > "Algorithm Geeks" group. >> > > To post to this group, send email to algogeeks@googlegroups.com. >> > > To unsubscribe from this group, send email to >> > > algogeeks+unsubscr...@googlegroups.com. >> > > For more options, visit this group at >> > >http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text - >> > >> > - Show quoted text - >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > Warm Regards, > Sunny T > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
