Hi Guys,
I have a O(n) solution for this problem:
/*
* Input: "my name is ram"
* Output: "ram is name my"
* Approach: Divide the string into tokens and store the token pointers on a
* stack. Pull them up to display output.
* */
#include <string.h>
#define MAX_WORDS_PER_STRING 100
#define MAX_STRING_LENGTH 512
int stack[MAX_WORDS_PER_STRING]; // maximum 100 words
int top; // stack top pointer
void push(int Item)
{
stack[top++] = Item;
}
int pop()
{
return stack[--top];
}
int main()
{
char InStr[MAX_STRING_LENGTH] = "my name is ram";
int ii = 0, NewWord = 1, len = 0;
//printf("Input string");
//scanf("%s",InStr);
len = strlen(InStr);
while(ii < len) {
if(InStr[ii] == ' ') {
/* replace black space with '\0' */
InStr[ii] = '\0';
if(InStr[ii+1] != ' ') NewWord = 1;
} else {
if(NewWord) {
push(ii);
NewWord = 0;
}
}
ii++;
}
/* Now print the words from stack */
while(1) {
ii = pop();
printf("%s ",(char *)&InStr[ii]);
if(ii == 0) break;
}
}
-Dinesh Bansal
On Wed, Jul 6, 2011 at 9:49 PM, Navneet Gupta <navneetn...@gmail.com> wrote:
> I think somebody on this thread has asked this question but i am not
> able to find that.
>
> Question was if a string is like "my name is ram", then output should
> be "ram is name my".
>
> Wrote the code for same, so sharing.
>
> #include<iostream>
> #include<string>
> using namespace std;
>
> void SwapStringChars(string &str, int pos1, int pos2)
> {
> char ch = str[pos1];
> str[pos1] = str[pos2];
> str[pos2] = ch;
> }
>
> void reverseString(string &str, int left, int right)
> {
> for(int i = left ; i <= left + (right-left)/2 ; i++)
> SwapStringChars(str, i, right + left -i));
> }
>
> void reverseWordsInString(string &str)
> {
> char space = ' ';
> int len = str.length();
> int startIndex = 0, endIndex = 0;
> while(endIndex < len - 1)
> {
> while(str[endIndex] != space && endIndex < len)endIndex++;
> reverseString(str, startIndex, endIndex-1);
> startIndex = endIndex;
> while(str[startIndex] == space)startIndex++;
> endIndex = startIndex;
> }
> }
>
> int main()
> {
> string str;
> cout<<"\nEnter enter the string :";
> getline(cin,str);
>
> //Reverse whole string at once
> reverseString(str, 0, str.length() - 1);
>
> //Reverse Individual words in string
> reverseWordsInString(str);
> cout<<str;
> cin.get();
> return 0;
> }
>
> --
> Regards,
> Navneet
>
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>
--
Dinesh Bansal
The Law of Win says, "Let's not do it your way or my way; let's do it the
best way."
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