then the version of spoj compiler for d must be belonging to an entirely
different world.I have solved a few problems using D and it had entirely
different syntax
On Thu, Jul 14, 2011 at 9:39 AM, shilpa gupta <shilpagupta...@gmail.com>wrote:
> if you have any doubt than run it i have done so......it is running ....
>
> On Thu, Jul 14, 2011 at 9:38 AM, saurabh singh <saurab...@gmail.com>wrote:
>
>> By the way I am no master of D but isn't it compilation error?
>> D was made to imitate java concept of importing libraries....So its a
>> compile error anyway,:)
>>
>> On Thu, Jul 14, 2011 at 9:30 AM, sanjay ahuja <sanjayahuja.i...@gmail.com
>> > wrote:
>>
>>> because your type is int (signed) and not unsigned..make it unsigned
>>> you will understand why is like this!
>>>
>>>
>>> On Thu, Jul 14, 2011 at 9:27 AM, John Hayes <agressiveha...@gmail.com>
>>> wrote:
>>> > @saurabh ....why in 2's complement form ?
>>> >
>>> > On Thu, Jul 14, 2011 at 9:21 AM, saurabh singh <saurab...@gmail.com>
>>> wrote:
>>> >>
>>> >> There is nothing wrong going wrong in the code shilpa.
>>> >> It specifies bit field
>>> >> a has now only 1 bit
>>> >> b has 2 bit.
>>> >> when u write t.a=6=(0110) it is stored as 0.
>>> >> while when u write t.b=2 it is stored as 10 which in 2's complement
>>> its
>>> >> -2.
>>> >> check size of t if you doubt me.
>>> >> On Thu, Jul 14, 2011 at 9:11 AM, shilpa gupta <
>>> shilpagupta...@gmail.com>
>>> >> wrote:
>>> >>>
>>> >>> in second problem a:1 and b:3 means default initialization but not in
>>> c
>>> >>> it is D programming language but u may b trying to compile it with c
>>> >>> complier
>>> >>> that's why it is showing wrong result..........if u will compile it
>>> with
>>> >>> D language compiler than it will print 6 and 2.....and if u will not
>>> >>> initialize them again with 6 and 2 then it will print 1 and 2
>>> >>>
>>> >>>
>>> >>> On Thu, Jul 14, 2011 at 8:27 AM, John Hayes <
>>> agressiveha...@gmail.com>
>>> >>> wrote:
>>> >>>>
>>> >>>> Hey Guys, plz help me in getting these 2 C output problems
>>> >>>>
>>> >>>> 1st problem
>>> >>>>
>>> >>>> #include<stdio.h>
>>> >>>> int main()
>>> >>>> {
>>> >>>> short int a,b,c;
>>> >>>> scanf("%d%d",&a,&b);
>>> >>>> c=a+b;
>>> >>>> printf("%d",c);
>>> >>>> return 0;
>>> >>>> }
>>> >>>> INPUT-
>>> >>>> 1 1
>>> >>>> OUTPUT
>>> >>>> 1
>>> >>>> i am not getting why 1 is coming in the output.....what difference
>>> is
>>> >>>> using short making in the code ???
>>> >>>> Problem No. 2
>>> >>>> #include<stdio.h>
>>> >>>> main()
>>> >>>> {
>>> >>>> struct
>>> >>>> {
>>> >>>> int a:1;
>>> >>>> int b:2;
>>> >>>> }t;
>>> >>>> t.b=6;
>>> >>>> t.a=2;
>>> >>>> printf("%d %d",t.a,t.b);
>>> >>>> }
>>> >>>> OUTPUT
>>> >>>> 0 -2
>>> >>>> What does the statement a:1 and b:1 mean and what are they
>>> doing.....i
>>> >>>> am seeing them first time ever...hence not able to get the
>>> output....if
>>> >>>> someone has any idea plz help !!
>>> >>>>
>>> >>>> --
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>>> >>>
>>> >>>
>>> >>>
>>> >>> --
>>> >>> shilpa gupta
>>> >>> b tech 2nd year
>>> >>> computer science and engineering
>>> >>> mnnit allahabad
>>> >>>
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>>> >>
>>> >>
>>> >>
>>> >> --
>>> >> Saurabh Singh
>>> >> B.Tech (Computer Science)
>>> >> MNNIT ALLAHABAD
>>> >>
>>> >>
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>>>
>>>
>>>
>>> --
>>> Sanjay Ahuja,
>>> Analyst, Financing Prime Brokerage
>>> Nomura Securities India Pvt. Ltd
>>>
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>>>
>>
>>
>> --
>> Saurabh Singh
>> B.Tech (Computer Science)
>> MNNIT ALLAHABAD
>>
>>
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>
>
>
> --
> shilpa gupta
> b tech 2nd year
> computer science and engineering
> mnnit allahabad
>
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--
Saurabh Singh
B.Tech (Computer Science)
MNNIT ALLAHABAD
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