@Anatony
the output will be compiler dependent
res1 is not defined .. as C don't allow to change the value of a variable
more than once between a sequence point..
A sequence point occur while assigning a value , calling a function or
returning from it..
Hence both res1 and res2 would give arbitary results..
On Sat, Jul 16, 2011 at 1:45 AM, Antony Kotre <antonyko...@gmail.com> wrote:
> can any tell and explain the output of following code
>
> #include<stdio.h>
> main()
> { int a =5, b=5;
> int res1=(++a)+(++a)+(++a);
> int res2=(++b)+(++b)*10+(++b)*100;
>
> printf("%d\n%d\n",res1,res2);
> }
>
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