HI,
Q1: Destructor of B is not called because it doesn't have Run time type
information as there is no virtual function.
By have a declaration like A *b= new B(); Application only know that type
of object b is A so when this object get destroyed, only Class A destructor
is called.
Q2: Virtual Call have minimum size of Vbptr ( virtual pointer) and size of
any pointer(address) on 32 bit architecture is 4 bytes.
On Sat, Jul 16, 2011 at 10:51 PM, Anika Jain <anika.jai...@gmail.com> wrote:
> Q.1 what is the output of following program?
>
> #include <iostream>
> using namespace std;
> class A
> {
> public:
> A()
> { cout<<"Constructing A"<<endl;
> }
>
> ~A()
> { cout<<"Destructing A"<<endl;
> }
> };
> class B : public A
> {
> public:
> B()
> {
> cout<<"Constructing B"<<endl;
> }
> ~B()
> {cout<<"Destructing B"<<endl;
>
> }
> };
> int main()
> {
> A *b=new B;
> delete b;
> }
> how is its output as:
>
> constructing A
> constructing B
> destructing B
> ??
>
>
> Q2. Determine output.
> class A
> { int a;
> public:
>
> virtual void f()
> {
> }
> };
> class B : private A
> { int b;
> public:
> void f()
> {
> }
> };
> int main()
> {
> cout<<sizeof(A)<<endl;
> cout<<sizeof(B)<<endl;
>
> }
> its output is:
> 8 12
>
> virtual functions do occupy 4 bytes ?? how??
>
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