one way is through the log concept: log(A/B)=logA-logB antilog(logA-logB) will give u log(A/B) without using division operator... but this will work iff there is a log function and an antilogfunction in the math.h header file...
-- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/i5jBog0xFIQJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.