Thanks a lot :)
On Mon, Jul 18, 2011 at 2:48 AM, Piyush Sinha <ecstasy.piy...@gmail.com>wrote:
> the output will be (b)
> before looking for the reason, you should know the syntax of printf
>
> *int printf(const char *format,....)*
>
> the function at the string after the comma operator only if the format
> string aks for any format specifier like %d or %f etc...u can try it like
> this also in normal main function
>
> *printf("piyush","sinha");
>
> *It wil compile and run successfully...and u can guess the output too....
> :)*
> *
> On Mon, Jul 18, 2011 at 2:19 AM, aditi garg <aditi.garg.6...@gmail.com>wrote:
>
>> #include<stdio.h>
>> #define FUN(arg) do\
>> {\
>> if(arg)\
>> printf("have fun...","\n");\
>> } while(i--)
>> void main()
>> {int i=2;
>> FUN(i<3);
>> }
>>
>> A.have fun..
>> have fun..
>> have fun..
>> B.have fun..have fun..have fun..
>> C.Error : cannot use instructions in macro
>> D.No output
>>
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>
>
> --
> *Piyush Sinha*
> *IIIT, Allahabad*
> *+91-7483122727*
> * <https://www.facebook.com/profile.php?id=100000655377926> "NEVER SAY
> NEVER"
> *
>
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--
Aditi Garg
Undergraduate Student
Electronics & Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
New Delhi
9718388816
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