In that case only the size of hash table will be required to increase.Any
possible o(1) space o(n) soln?

On Mon, Jul 18, 2011 at 7:43 PM, shady <sinv...@gmail.com> wrote:

> O(n) for both space and time.......
> count the number of times each character is coming = O(n) space in worst
> case
> start from the string beginning if character has count == 1 print it O(n)
> in worst case
> this works with ASCII characters... since we can hash them on their values
> 0, 255.......... for languages like hindi, german don't know :)
>
>
> On Mon, Jul 18, 2011 at 7:35 PM, hary rathor <harry.rat...@gmail.com>wrote:
>
>> can anybody tell me in O(n)  solution,?
>>
>>
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-- 
Saurabh Singh
B.Tech (Computer Science)
MNNIT ALLAHABAD

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