may be im wrong....but i read it somewhere about it...the arguments of
a function are evaluated in a associativity that is compiler
dependent...
for ex...
printf("%d %d %d" ,fun1(),fun2(),fun3());
the order in which functions are evaluated are compiler dependent....
On Fri, Jul 22, 2011 at 7:20 PM, Abhinav Verma
<abhinav.verma6...@gmail.com> wrote:
> Its not the associativity which is undefined (Associativity has been defined
> clearly by the C Standards for each and every operator). Its the order of
> evaluation between 2 sequence points which is undefined and hence
> compiler-dependent.
> On gcc version 4.4.3, output generated is 5551. On some other compiler, the
> output may differ.
>
> On Fri, Jul 22, 2011 at 6:09 PM, Gaurav Popli <abeygau...@gmail.com> wrote:
>>
>> associativity rule is compiler dependent ...thats why undefined...
>>
>> On Fri, Jul 22, 2011 at 5:46 PM, Kamakshii Aggarwal
>> <kamakshi...@gmail.com> wrote:
>> > undefined behaviour.
>> > since value of i is changing more than once between two sequence
>> > points..
>> > On Fri, Jul 22, 2011 at 5:42 PM, suresh srinivasan <suree...@gmail.com>
>> > wrote:
>> >>
>> >> Output:
>> >> 5,4,3,1
>> >>
>> >> Explanation:
>> >> Since the brackets acts as right precedence, the execution of the
>> >> statement is from right to left. The comma separates the individual.
>> >> For i++, it prints the current 'i' value and increments it by 1.
>> >> For ++i, it increments the value by 1 and prints the updated value of
>> >> 'i'.
>> >> --
>> >> Regards,
>> >> Suresh.S
>> >>
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>> >
>> >
>> > --
>> > Regards,
>> > Kamakshi
>> > kamakshi...@gmail.com
>> >
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