+1 to t3rminal
On Jun 12, 11:38 pm, T3rminal <piyush....@gmail.com> wrote:
> @all
> Stop guessing and making your own standards. C standards haven't
> defined anything (though in gcc arguments are processed from left to
> right) about processing arguments in a function call. And sentence
> like "assgnment to a preincrement expression is delayed vry mch...."
> have no meaning . Seriously which book have you referred.
> This all fall in category of UNDEFINED BEHAVIOR.
> If a value of a variable is changed more than once between two
> sequence points, it give rises to side-effect which lead to undefined
> behavior.
> There is no explanation for this output supported by C standards.
> On Jun 12, 8:14 pm, varun pahwa <varunpahwa2...@gmail.com> wrote:
>
>
>
>
>
>
>
> > yes the output is compiler dependent.
>
> > On Sun, Jun 12, 2011 at 6:35 AM, nicks <crazy.logic.k...@gmail.com> wrote:
> > > but program by anika is giving *7 6 8* on gcc.....but *7 6 6 *on
> > > dev-cpp...........i am wondering if the output is compiler dependent !!
>
> > > On Sun, Jun 12, 2011 at 6:33 AM, nicks <crazy.logic.k...@gmail.com> wrote:
>
> > >> no it's
> > >> a=1 b=1
> > >> i=2
>
> > >> i ran it on gcc (linux ubuntu 11.04)
>
> > >> On Sun, Jun 12, 2011 at 6:26 AM, sanjay ahuja <sanjayahuja.i...@gmail.com
> > >> > wrote:
>
> > >>> with GCC the above code gives a = 1 and b = 2
>
> > >>> On Sun, Jun 12, 2011 at 6:39 PM, nicks <crazy.logic.k...@gmail.com>
> > >>> wrote:
> > >>> > @himanshu....what abt this ??
>
> > >>> > #include<stdio.H>
> > >>> > # include <conio.h>
> > >>> > int i=2;
> > >>> > main()
> > >>> > {
> > >>> > void add();
> > >>> > add(i++,--i);
> > >>> > printf("\ni=%d \n",i);system("pause");
> > >>> > }
> > >>> > void add(int a ,int b)
> > >>> > {
> > >>> > printf("\na=%d b=%d",a,b);
> > >>> > }
>
> > >>> > OUTPUT -
> > >>> > a=1 b=1
> > >>> > i=2
>
> > >>> > acc. to ur logic output should be -
> > >>> > a=1 b=2
> > >>> > i=2
>
> > >>> > On Sun, Jun 12, 2011 at 5:42 AM, Anika Jain <anika.jai...@gmail.com>
> > >>> wrote:
>
> > >>> >> thanks himanshu finally i got the reason!!
> > >>> >> :)
>
> > >>> >> On Sun, Jun 12, 2011 at 5:59 PM, himanshu kansal
> > >>> >> <himanshukansal...@gmail.com> wrote:
>
> > >>> >>> @anika:cz on gcc arguemnts r eval frm right to left and assgnment to
> > >>> a
> > >>> >>> pre increment expression is delayed vry mch....
> > >>> >>> so on eval frm right to left....
> > >>> >>> frst a is incremented...(6) bt remember d new value is nt pushed on
> > >>> stack
> > >>> >>> till nw....(cz assgnmnt is delayed)
> > >>> >>> thn next value is 6...nd thn a is incremented.....here being a post
> > >>> >>> increment op....assgnmnt is made 1st (2nd arg to fun is 6)and a is
> > >>> >>> incrementd to 7....
> > >>> >>> simalrly.....assgnmnt is made(1st arg is 7) and a is incremnted to
> > >>> 8.....
> > >>> >>> nw d assgnmnt is made to the 3rd arg(d assgnmnt whch ws delayed till
> > >>> >>> nw).....hence 3rd arg becomes 8.....
> > >>> >>> so it prints 7 6 8......
>
> > >>> >>> On Sun, Jun 12, 2011 at 5:33 PM, Anika Jain <anika.jai...@gmail.com>
> > >>> >>> wrote:
>
> > >>> >>>> can anybody explain that in following code y output is coming to
> > >>> >>>> be:
> > >>> 7 6
> > >>> >>>> 8
>
> > >>> >>>> void call(int a,int b,int c)
> > >>> >>>> {
> > >>> >>>> printf("%d %d %d",a,b,c);
> > >>> >>>> }
>
> > >>> >>>> int main()
> > >>> >>>> {
> > >>> >>>> int a=5;
> > >>> >>>> call(a++,a++,++a);
> > >>> >>>> return 0;
> > >>> >>>> }
>
> > >>> >>>> On Sat, Jun 11, 2011 at 8:21 PM, PRAMENDRA RATHi rathi
> > >>> >>>> <prathi...@gmail.com> wrote:
>
> > >>> >>>>> IN second program:
> > >>> >>>>> in function value are always push in the stack from right.
> > >>> >>>>> so first value is --i that will make i=1 and value 1 will be
> > >>> >>>>> passed
> > >>> to
> > >>> >>>>> function
> > >>> >>>>> and
> > >>> >>>>> after that i++ that's means i will be passed.
> > >>> >>>>> so 1 will be passed and after passing value. i will changed to 2.
>
> > >>> >>>>> if u want to know why reverse order than can go through:
>
> > >>> >>>>>http://cs.nyu.edu/courses/fall03/V22.0201-003/c_param.html
> > >>> >>>>> -----------------------------------------
> > >>> >>>>> PRAMENDRA RATHI
> > >>> >>>>> NIT ALLAHABAD
>
> > >>> >>>>> On Sat, Jun 11, 2011 at 7:28 PM, Vishal Thanki <
> > >>> vishaltha...@gmail.com>
> > >>> >>>>> wrote:
>
> > >>> >>>>>> In 1st program, 2nd printf requires one more argument. And
> > >>> basically
> > >>> >>>>>> %a is used for printing a double value in hex. see "man 3
> > >>> >>>>>> printf".
>
> > >>> >>>>>> On Sat, Jun 11, 2011 at 5:29 PM, nicks <
> > >>> crazy.logic.k...@gmail.com>
> > >>> >>>>>> wrote:
> > >>> >>>>>> > Hello friends..plz help me in understanding the following C
> > >>> Output
>
> > >>> >>>>>> > first one is --
>
> > >>> >>>>>> > #include<stdio.h>
> > >>> >>>>>> > #include<conio.h>
> > >>> >>>>>> > main()
> > >>> >>>>>> > {
> > >>> >>>>>> > int a=5;
> > >>> >>>>>> > printf("a=%d\n",a);
> > >>> >>>>>> > printf("%a=%d",a);
> > >>> >>>>>> > getch();
> > >>> >>>>>> > }
> > >>> >>>>>> > OUTPUT -
> > >>> >>>>>> > a=5
> > >>> >>>>>> > 0x1.2ff380p-1021=4199082
>
> > >>> >>>>>> > and the other one is --
>
> > >>> >>>>>> > #include<stdio.H>
> > >>> >>>>>> > # include <conio.h>
> > >>> >>>>>> > int i=2;
> > >>> >>>>>> > main()
> > >>> >>>>>> > {
> > >>> >>>>>> > void add();
> > >>> >>>>>> > add(i++,--i);
> > >>> >>>>>> > printf("\ni=%d \n",i);system("pause");
> > >>> >>>>>> > }
> > >>> >>>>>> > void add(int a ,int b)
> > >>> >>>>>> > {
> > >>> >>>>>> > printf("\na=%d b=%d",a,b);
> > >>> >>>>>> > }
>
> > >>> >>>>>> > OUTPUT -
> > >>> >>>>>> > a=1 b=1
> > >>> >>>>>> > i=2
>
> > >>> >>>>>> > --
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> > >>> >>> --
>
> > >>> >>> Regards
> > >>> >>> Himanshu Kansal
> > >>> >>> Msc Comp. sc.
> > >>> >>> (University of Delhi)
>
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> > >>> --
> > >>> Sanjay Ahuja,
> > >>> Analyst, Financing Prime Brokerage
> > >>> Nomura Securities India Pvt. Ltd
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> > --
> > Varun Pahwa
> > B.Tech (IT)
> > 7th Sem.
> > Indian Institute of Information Technology Allahabad.
> > Ph : 09793899112 ,08011820777
> > Official Email :: rit2008...@iiita.ac.in
> > Another Email :: varunpahwa.ii...@gmail.com
>
> > People who fail to plan are those who plan to fail.
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