Declare the character strings
char five[7];
char four[7];
int three;
char two[7];
char one[7];

int his order and we get the correct output. But i dont know y?Its something
to do with Memory location where the strings are defined.










*Muthuraj R.
4TH Year BE.**
Information Science Dept*
*PESIT, Bengaluru .
*




On Sat, Jul 23, 2011 at 10:57 PM, shady <sinv...@gmail.com> wrote:

> anyone ?
>
>
> On Sun, Jul 24, 2011 at 2:38 AM, Anika Jain <anika.jai...@gmail.com>wrote:
>
>> in this in scanf one,two, four five will b thr, no & thr..
>>
>> and sumbody plz tell afterwards this change why the o/p is
>> this is 10 times charlie
>> thisis10charlie
>>
>> why in 'four' empty string is going??
>>
>>
>> On Sat, Jul 23, 2011 at 9:37 PM, geek forgeek <geekhori...@gmail.com>wrote:
>>
>>> #include<stdio.h>
>>> main()
>>> {
>>>     char outline[50];
>>>     char one[7],two[7],four[7],five[7];
>>>     int three;
>>>     sprintf(outline,"this is %d times %s \n",10,"charlie");
>>>     printf("%s",outline);
>>>     sscanf(outline,"%s %s %d %s %s",&one,&two,&three,&four,&five);
>>>     printf("%s",one);
>>>     printf("%s",two);
>>>     printf("%d",three);
>>>     printf("%s",four);
>>>     printf("%s",five);
>>> }
>>>
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