anyway, the code i posted is buggy.. doesn't work for "k=3".. don't use it :)
On Tue, Jul 26, 2011 at 1:02 PM, Vishal Thanki <vishaltha...@gmail.com> wrote:
> @ankur, i think 1,2 and 2,1 would be same as set theory.. CMMIW.
> following is the code..
>
> #include <stdio.h>
> #include <stdlib.h>
>
> void print_comb(int *a, int len)
> {
> int tlen = len;
> int i, j, k;
>
> for (i=0;i<5;i++) {
> for (j=i+1; j<4;j++) {
> printf("%d ", a[i]);
> k=j;
> while(tlen-1 > 0) {
> printf("%d ", a[k]);
> k++;
> tlen--;
> }
> printf("\n");
> tlen = len;
> }
> }
> }
>
> int main(int argc, char *argv[])
> {
> int len = atoi(argv[1]);
> int arr[] = {1,2,3,4};
> print_comb(arr, len);
> return 0;
> }
>
>
> On Tue, Jul 26, 2011 at 1:01 PM, Ankur Garg <ankurga...@gmail.com> wrote:
>> Hi
>> Dont u think the subsets will also be
>> {2,1}
>> {3,1}
>> {3,2}
>> {4,1}
>> {4,2}
>> {4,3}
>> On Tue, Jul 26, 2011 at 11:59 AM, sumit <sumitispar...@gmail.com> wrote:
>>>
>>> Given an array of size n, print all the possible subset of array of
>>> size k.
>>> eg:-
>>> input:
>>> a[]={1,2,3,4}, k = 2
>>> output:
>>> 1,2
>>> 1,3
>>> 1,4
>>> 2,3
>>> 2,4
>>> 3,4
>>>
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